Wndsn Sun Calculator
Companion to Wndsn Quadrant Telemeters: Low tech, high utility graphical distance computers from the Wndsn applied science lab.
By way of using a Wndsn Quadrant to measure local latitude and calculate declination for a given date, a number of values can be derived through further Quadrant computations.
Knowing the noon altitude of the Sun, we can calculate the solar declination δ and vice versa.
The declination of the Sun is the angle between the Sun's rays and the equatorial plane of the Earth. The declination angle is the same for anywhere on Earth on a given day.
The equations are proof-of-concept formulas and ignore specifics like atmospheric refraction, etc. The calculated results are FOR EDUCATIONAL PURPOSES ONLY; some are exact, some are approximate, and some are simplified. Actual Sun data may vary significantly.
- Latitude φ:
- Instantaneous Sun altitude h:
General calculations for latitude
- Maximum solar altitude H on equinoxes for latitude given:
- Maximum solar altitude H on summer solstice for latitude given:
- Maximum solar altitude H on winter solstice for latitude given:
- Summer solstice sunrise αsr and sunset αss azimuth:
- Winter solstice sunrise αsr and sunset αss azimuth:
Diurnal calculations for latitude and declination or date
- Day #:
- Declination δ:
- Sunrise azimuth αsr:
- Sunset azimuth αss:
- Hour angle at sunrise tsr:
- Sun hours:
- Length of unequal Sun hour:
- Noon altitude H:
- Equation of time:
Instantaneous calculations for Sun altitude
- Hour angle t:
- Time to or from noon:
- Sun azimuth αs:
- Shadow length (of a stick with a height of 1 unit):
The display precision set is
.2. To change that, edit the variable
&digits=x in the URL where
0 <= x <= 9.
- Sun altitude at noon H from latitude:
H = (90° − φ) + δ
- Azimuth αsr of rising/setting sun:
cos αsr = sin δ / cos φ
- Hour angle tsr of rising/setting sun (from noon):
cos tsr = -tan φ * tan δ
- Hour angle t from instantaneous Sun altitude h:
sin t = (sin h - sin δ * sin φ) / (cos δ * cos φ)
- Sun azimuth αs for a given hour:
tan αs = (sin t / (sin φ * cos t)) - cos φ * tan δ
where H = Sun altitude at noon, h = instantaneous Sun altitude, t = hour angle, φ = latitude, and δ = declination.
1 rad = 57.3 deg 6.2832 rad = 360 deg = 6283.2 mil = 21,600 minutes (moa) 0.017453 rad = 1 deg = 17.453 mil = 60 minutes (moa) 0.0573 deg = 1 mil = 3.438 minutes (moa)